1+36x^2=65

Solution for 1+36x^2=65 equation:

1+36x^2=65

We move all terms to the left:

1+36x^2-(65)=0

We add all the numbers together, and all the variables

36x^2-64=0

a = 36; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·36·(-64)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*36}=\frac{-96}{72}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*36}=\frac{96}{72}
=1+1/3
$